-0.025x^2+0.45x+2=0

Solution for -0.025x^2+0.45x+2=0 equation:

-0.025x^2+0.45x+2=0

a = -0.025; b = 0.45; c = +2;
Δ = b2-4ac
Δ = 0.452-4·(-0.025)·2
Δ = 0.4025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.45)-\sqrt{0.4025}}{2*-0.025}=\frac{-0.45-\sqrt{0.4025}}{-0.05}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.45)+\sqrt{0.4025}}{2*-0.025}=\frac{-0.45+\sqrt{0.4025}}{-0.05}
$